C pattern printing?

Help me with printing these patterns in C:





*****


****


***


**


*








And one more:


1


2 2


3 3 3


4 4 4 4





Please give source code or logic.


I want thesse in the same pattern i showed plz.

C pattern printing?
#include %26lt;stdio.h%26gt;





int main (void)


{


int i, j;





for (i = 5; i %26gt; 0; i--)


{


for (j = i; j %26gt; 0; j--)


printf ("*");





printf ("\n");


}





return 0;


}


_____





#include %26lt;stdio.h%26gt;





int main (void)


{


int i, j;





for (i = 1; i %26lt;= 5; i++)


{


for (j = 1; j %26lt;= i; j++)


printf ("%d ", i);





printf ("\n");


}





return 0;


}
Reply:#include%26lt;stdio.h%26gt;


#include%26lt;conio.h%26gt;


int main()


{


int i,j;


clrscr();


for(i=5;i%26gt;0;i--)


{


for(j=0;j%26lt;i;j++)


printf("*");


printf("\n");


}


getch();


return 0;


}











#include%26lt;stdio.h%26gt;


#include%26lt;conio.h%26gt;


int main()


{


int i,j;


clrscr();


for(i=1;i%26lt;=4;i++)


{


for(j=0;j%26lt;i;j++)


printf("%d",i);


printf("\n");


}


getch();


return 0;


}
Reply:void main() {


int i=0;


int j=0;


int rows = 5;


for(i=0;i%26lt;rows;i++) {


for(j=0;j%26lt;(rows-i);j++) {


printf("*");


}


printf("\n");


}


for(i=0;i%26lt;rows;i++) {


for(j=0;j%26lt;i;j++) {


printf(i);


}


printf("\n");


}


}

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