its better that the code be in C or C++
I need the source code for multiplying two matrices with three nested loops.?
Here is an implementation in C++:
// For the matrix multiplication to work the following must hold:
// M1COLUMNS == M2ROWS
// The resulting matrix has the same rows as m1 and
// the same columns as m2
// You can change the following values as you like
const int M1Rows = 2;
const int M1COLUMNS = 4;
const int M2ROWS = 4;
const int M2COLUMNS = 3;
int resultRows = M1ROWS;
int resultColumns = M2COLUMNS;
int m1[M1Rows][M1COLUMNS];
int m2[M2ROWS][M2COLUMNS];
int result[resultRows][resultColumns];
int sum = 0;
// Here you have to initialize your m1 %26amp; m2 matrices
// Now here is the code to get the result of multiplying two
// matrices using 3 nested loops:
for(int x = 0; x %26lt; M1ROWS; x++)
{
for(int y = 0; y %26lt; resultColumns; y++)
{
for(int z = 0; z %26lt; M1COLUMNS; z++)
{
sum += (m1[x][z] * m2[z][y]);
}
result[x][y] = sum;
sum = 0;
}
}
Reply:Hmmm, this is a very cool one.
but I cant confirm that this is the right matrix, but this is the almost the same, that I used to type in my practical exams.
# include %26lt;stdio.h%26gt;
# include %26lt;conio.h%26gt;
void main()
{
int a[3][3] , b[3][3], c[3][3], i, j,k;
printf("\n enter matrix a 9 values : ");
for(i=0;i%26lt;3;i++)
for(j=0;j%26lt;3;j++)
scanf("%d",%26amp;a[i][i]);
printf("\n enter matrix b 9 values : ");
for(i=0;i%26lt;3;i++)
for(j=0;j%26lt;3;j++)
scanf("%d",%26amp;b[i][j]);
for(i=0;i%26lt;3;i++)
for(j=0;j%26lt;3;j++)
for(k=0;k%26lt;j;k++) // if you get error only this line has to be modified but dont wonder what can come, later ;)
c[i][j]=a[i][k] * b[k][j];
printf("\n multiplication matrix is : \n");
for(i=0;i%26lt;3;i++){
for(j=0;j%26lt;3;j++) {
printf("%d ",c[i][j]);
}
printf("\n");
}
getch();
}
warm regards,
K.A.G.S.
btw its C code
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